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Vector Cross Product 

on this page: ► calculating the cross product ► cross product properties ► cross product applications 
In order to understand the material on this page, you need to know some linear algebra, specifically, how to calculate the determinant of 2x2 and 3x3 matrices. You can find a quick review on the linear algebra page. 
Calculating The Cross Product 
The Cross Product is one way to 'multiply' two vectors (the other way is the dot product). Unlike the dot product, the cross product only makes sense when performed on two 3dim vectors. Taking the cross product of the two vectors \( 3\hat{i}+2\hat{j} \) and \( \hat{i}+\hat{j} \) is not possible, unless you mean \( 3\hat{i}+2\hat{j}+0\hat{k} \) and \( \hat{i}+\hat{j}+0\hat{k} \), in which case, you need to write out the \(\hat{k}\) term even if it is zero.
If we have two vectors, \(\vec{u}=\langle u_1, u_2, u_3 \rangle \) and \(\vec{v} = \langle v_1, v_2, v_3 \rangle \), we write the cross product of these two vectors as \( \vec{u} \times \vec{v} \).
The result of the cross product of two vectors is another vector. It's meaning is discussed later on this page. For now, let's focus on how we calculate the cross product.
To calculate the cross product, we use some linear algebra. If you haven't already, now would be good time to review the linear algebra page to make sure your skills calculating a 3x3 determinant are sharp. To calculate the cross product we calculate the following determinant.
\(
\vec{u} \times \vec{v} =
\begin{vmatrix}
\hat{i} & \hat{j} & \hat{k} \\
u_1 & u_2 & u_3 \\
v_1 & v_2 & v_3
\end{vmatrix}
\)
\( = (u_2 v_3  u_3 v_2)\hat{i}  (u_1 v_3  u_3 v_1)\hat{j} + (u_1 v_2  u_2 v_1)\hat{k} \)
Comments 
1. It is best NOT to memorize the last expression. Instead, set up and evaluate the determinant.
2. Remember to subtract the middle term.
3. It is important to set up the determinant correctly, i.e.
 The first row is the set of unit vectors.
 The second row is the first vector of the cross product.
 The third row is the second vector of the cross product.
The rows cannot be in any other order (more on this in the properties section below).
The name 'cross product' comes from the notation using '\(\times\)' between the two vectors. Just like with the dot product, it is important to use the '\(\times\)' between the vectors to indicate a cross product. Writing \(\vec{u} \vec{v} \) makes no sense and is considered incorrect notation.
Note: Recently we heard that what we call the 'determinant' above is not strictly a determinant but just a mnemonic device to calculate the cross product, since a true determinant consists of only numbers not vectors. We have not verified this at this time but it certainly could be true. When we verify it, we will update this page accordingly.
Okay, so let's watch a video clip discussing the cross product and its geometric interpretation.
PatrickJMT  geometric interpretation of the cross product  
Cross Product Properties 
Here are some cross product properties.
Algebraic Properties
Let \(\vec{u}\), \(\vec{v}\) and \(\vec{w}\) be vectors in space and let \(a\) be a scalar.
1. \(\vec{u} \times \vec{v} = (\vec{v} \times \vec{u})\)
2. \(\vec{u} \times (\vec{v}+\vec{w}) = (\vec{u} \times \vec{v}) + (\vec{u} \times \vec{w}) \)
3. \(a(\vec{u} \times \vec{v}) = (a\vec{u}) \times \vec{v} = \vec{u} \times (a\vec{v})\)
4. \(\vec{u} \times \vec{0} = \vec{0} \)
5. \( \vec{u} \times \vec{u} = \vec{0} \)
Notes:
 property 1 implies that the cross product is not commutative
 in property 2, the vector \(\vec{u}\) is on the left, so when it is distributed across the addition, it must remain on the left in both cases
 property 5 seems trivial but it is very powerful; later on this page, this will be discussed in more detail.
Here is a video with proofs of some of these algebraic properties.
Larson Calculus  proofs of some algebraic properties  
Geometric Properties
Let \(\vec{u}\) and \(\vec{v}\) be nonzero vectors in space and let \(\theta\) be the angle between \(\vec{u}\) and \(\vec{v}\).
6. \(\vec{u} \times \vec{v}\) is orthogonal to both \(\vec{u}\) and \(\vec{v}\).
7. \( \ \vec{u} \times \vec{v} \ = \\vec{u}\ \\vec{v}\ \sin \theta\)
8. \(\vec{u} \times \vec{v} = \vec{0} \) if and only if \(\vec{u}\) is a scalar multiple of \(\vec{v}\)
9. \( \ \vec{u} \times \vec{v} \ \) represents the area of the parallelogram formed with \(\vec{u}\) and \(\vec{v}\) as adjacent sides.
Notes:
 for the geometric properties, both vectors must be nonzero; this is not a requirement in the algebraic properties
 notice in property 7, the cross product involves the sine of angle \(\theta\) while the dot product involves the cosine of the angle
 as mentioned in property 9, the cross product is the area of a parallelogram; here is a great video that discusses this in more detail.
Dr Chris Tisdell  Cross Product and Area of Parallelogram  
Here is a video with proofs of some of these geometric properties.
Larson Calculus  proofs  
There is a simple rule to use when you need to know the direction of the resulting vector from the cross product. It's called the right hand rule. The idea is to lay out your hand with all fingers straight out. Place the middle of your hand at the point of intersection of the two vectors involved in the cross product with your fingers in the direction of the first vector. Fold your fingers in the direction of the second vector. Your thumb will then be pointing in the direction of the result of the cross product. Here is a quick video showing this idea.
Right Hand Rule for Cross Products  
All this information may be a bit overwhelming. So let's take a few minutes and watch this video. He explains the cross product very well and shows some examples.
Dr Chris Tisdell  Cross product of vectors  
Cross Product Applications 
Triple Scalar Product
Triple Scalar Product
The triple scalar product is a result of combining the dot product with the cross product. First, let's define what it is and then discuss a couple of properties.
Definition and Notation 
If we have three vectors in space,
\(\vec{u} = u_x\hat{i}+u_y\hat{j}+u_z\hat{k}\),
\(\vec{v} = v_x\hat{i}+v_y\hat{j}+v_z\hat{k}\) and
\(\vec{w} = w_x\hat{i}+w_y\hat{j}+w_z\hat{k}\), then the triple scalar product is defined to be
\( \vec{u} \cdot (\vec{v} \times \vec{w}) \)
The calculation of this can be done as follows
\( \vec{u} \cdot (\vec{v} \times \vec{w}) =
\begin{vmatrix}
u_x & u_y & u_z \\
v_x & v_y & v_z \\
w_x & w_y & w_z
\end{vmatrix}
\)
[ proof ]
The triple scalar product is so named because the result is a scalar. [For comparison, see the triple vector product panel below.]
Properties  The triple scalar product can also be evaluated in one of the following forms.
\( \vec{a} \cdot (\vec{b} \times \vec{c}) =
\vec{b} \cdot (\vec{c} \times \vec{a}) =
\vec{c} \cdot (\vec{a} \times \vec{b})
\)
The parentheses may be omitted since evaluating the dot product first yields a scalar and it doesn't make sense to take the cross product of a scalar with a vector.
This property also holds \(
[\vec{a} \cdot (\vec{b} \times \vec{c})]\vec{a} =
(\vec{a} \times \vec{b}) \times (\vec{a} \times \vec{c})
\)
When the triple scalar product is zero, the 3 vectors are coplanar.
Applications  Geometrically, the triple scalar product \( \vec{a} \cdot (\vec{b} \times \vec{c} ) \) is the (signed) volume of the parallelepiped defined by the three vectors given (see figure on the right). The word 'signed' means that the result can be positive or negative depending on the orientation of the vectors.
You can probably now see that when the 3 vectors are coplanar, the parallelepiped is flat and has no volume, so the triple scalar product is zero.
Other Names For the Triple Scalar Product 
 scalar triple product
 mixed product
 box product
Here are several videos that explains this in more detail. The first two are especially good and the third contains a proof.
Dr Chris Tisdell  Scalar triple product  
Dr Chris Tisdell  Scalar triple product and volume  
Larson Calculus Proof  Geometric Property of the Triple Scalar Product  
Triple Vector Product
Triple Vector Product
The triple vector product (or vector triple product, as it is sometimes called) is so named because the result is a vector. [For comparison, see the triple scalar product panel above.]
When you have three vectors, \( \vec{u}\), \(\vec{v}\) and \(\vec{w}\), the triple vector product is defined as \( \vec{u} \times \vec{v} \times \vec{w} \).
Triple Scalar Product Proof
Theorem: Triple Scalar Product 

If we have three vectors in space, 
Proof   To prove this, we will calculate \( \vec{u} \cdot (\vec{v} \times \vec{w}) \) and then calculate the determinant to show that we get the same result. Let's start with the cross product.
\( \vec{v} \times \vec{w} =
\begin{vmatrix}
\hat{i} & \hat{j} & \hat{k} \\
v_x & v_y & v_z \\
w_x & w_y & w_z
\end{vmatrix}
= \) \(
(v_y w_z  v_z w_y)\hat{i}  \) \(
(v_x w_z  w_x v_z)\hat{j} + \) \(
(v_x w_y  w_x v_y)\hat{k} \)
Taking the dot product of \(\vec{u}\) and the last equation gives us
\( (u_x\hat{i}+u_y\hat{j}+u_z\hat{k}) \cdot [ (v_y w_z  v_z w_y)\hat{i}  \) \(
(v_x w_z  w_x v_z)\hat{j} + \) \(
(v_x w_y  w_x v_y)\hat{k} ] = \) \(
u_x(v_y w_z  v_z w_y)  \) \(
u_y(v_x w_z  w_x v_z) + \) \(
u_z(v_x w_y  w_x v_y) \)
We could certainly multiply the components of vector \(\vec{u}\) through each factor, but for reasons you will see later, we will leave the equation as it is. To sum up, we have calculated
\( \vec{u} \cdot (\vec{v} \times \vec{w}) = \) \(
u_x(v_y w_z  v_z w_y)  \) \(
u_y(v_x w_z  w_x v_z) + \) \(
u_z(v_x w_y  w_x v_y) ~~~~~ (1) \)
Okay, now let's calculate the determinant
\(
\begin{vmatrix}
u_x & u_y & u_z \\
v_x & v_y & v_z \\
w_x & w_y & w_z
\end{vmatrix}
\)
We will go across the top row (although going down the first column will give us the same result, going across the top row makes the algebra come out the way want it to).
\(
\begin{vmatrix}
u_x & u_y & u_z \\
v_x & v_y & v_z \\
w_x & w_y & w_z
\end{vmatrix} = \) \(
u_x(v_y w_z  v_z w_y)  \) \(
u_y(v_x w_z  w_x v_z) + \) \(
u_z(v_x w_y  w_x v_y)
\)
Notice this last equation is the same as equation (1) above. This is easier to see since we did not multiply out all factors in Equation (1). So, we have shown
\( \vec{u} \cdot (\vec{v} \times \vec{w}) =
\begin{vmatrix}
u_x & u_y & u_z \\
v_x & v_y & v_z \\
w_x & w_y & w_z
\end{vmatrix}
\) [qed]
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Practice Problems 

Instructions   Unless otherwise stated, give all your answers in exact form. For angles, give your answers in radians to 3 decimal places.
Level A  Basic 
Practice A01  

Given \(\vec{A}=2\hat{i}+3\hat{j}+4\hat{k}\) and \(\vec{B}=\hat{i}+3\hat{k}\), calculate the cross product \(\vec{A}\times\vec{B}\).  
answer 
solution 
Practice A02  

Given \(\vec{A}=2\hat{i}+3\hat{j}+4\hat{k}\) and \(\vec{B}=\hat{i}+3\hat{k}\), use the cross product to find the angle between \(\vec{A}\) and \(\vec{B}\).  
answer 
solution 
Practice A03  

Find a unit vector that is perpendicular to \(\vec{A}=\hat{i}+2\hat{j}+3\hat{k}\) and \(\vec{B}=3\hat{i}+2\hat{j}+\hat{k}\).  
answer 
solution 
Practice A04  

Show that the vectors \(\vec{A} = 2\hat{i}3\hat{j}+4\hat{k}\), \(\vec{B} = 6\hat{i}+2\hat{j}+\hat{k}\) and \(\vec{C} = 6\hat{i}+10\hat{j}7\hat{k}\) are coplanar.  
answer 
solution 
Practice A05  

Show that the vectors \(\vec{A}=2\hat{i}+3\hat{j}+6\hat{k}\) and \(\vec{B}=6\hat{i}+2\hat{j}3\hat{k}\) are perpendicular.  
answer 
solution 
Practice A06  

Find a unit vector that is perpendicular to \(\vec{A}=2\hat{i}+3\hat{j}+6\hat{k}\) and \(\vec{B}=6\hat{i}+2\hat{j}3\hat{k}\).  
answer 
solution 
Practice A07  

Given \(\vec{A}=\hat{i}2\hat{j}+2\hat{k}\) and \(\vec{B}=3\hat{i}\hat{j}\hat{k}\) calculate the cross product \(\vec{A}\times\vec{B}\).  
answer 
solution 
Practice A09  

Given \(\vec{A}=\hat{i}2\hat{j}+2\hat{k}\), \(\vec{B}=3\hat{i}\hat{j}\hat{k}\) and \(\vec{C}=\hat{i}\hat{k}\), calculate the triple scalar product \(\vec{A}\cdot\vec{B}\times\vec{C}\).  
answer 
solution 
Practice A10  

Given \(\vec{A}=\hat{i}2\hat{j}+2\hat{k}\), \(\vec{B} = 3\hat{i}\hat{j}\hat{k}\) and \(\vec{C}=\hat{i}\hat{k}\), calculate the triple vector product \(\vec{A}\times\vec{B}\times\vec{C}\).  
answer 
solution 
Practice A11  

Calculate the cross product of the vectors \(\vec{a}=\langle5,1,2\rangle\) and \(\vec{b}=\langle3,2,4\rangle\).  
solution 
Practice A12  

Calculate the cross product of the vectors \(\vec{a}=\hat{i}\hat{j}+3\hat{k}\) and \(\vec{b}=2\hat{i}+3\hat{j}+\hat{k}\).  
solution 
Practice A13  

Calculate the cross product of the vectors \(\vec{a}=\langle2,3\rangle\) and \(\vec{b}=\langle4,5\rangle\).  
solution 
Practice A14  

Calculate the cross product of the vectors \(\vec{a}=\langle5,1,4\rangle\) and \(\vec{b}=\langle1,0,2\rangle\).  
solution 