17Calculus Precalculus - Solving Nonlinear Systems of Equations
Types of Systems of Equations
Basics of linear systems with the same number of equations as unknowns - covered on the main linear systems page |
Linear with fewer equations than unknowns - covered on the dependent systems page |
Non-Linear - covered on this page |
Recommended Books on Amazon | ||
|---|---|---|
  |
  |
  |
Getting Started
Solving systems of nonlinear equations can be done using techniques you have already learned with linear equations, substitution and elimination. Knowing which one to use is based on the form of the equations and, if you carefully look at the systems, usually one of the techniques will seem to work best. Here are some ideas to get you started.
1. If you have terms that with powers, try elimination first. It is best not to solve for a variable under a power. For example, if one of your equations is \(y=x^2\), do not try to solve for x in order to use substitution. This will introduce a complexity that can lead to incomplete and incorrect answers.
2. If there is an obvious substitution, try to substitute cautiously. Sometimes substitution can get messy. Other times it can simplify the equations significantly.
3. You may end up with a quadratic. In this case, completing the square will help.
Difference From Linear Systems
Although we use the same techniques (substitution and elimination), we may end up with more than one solution. If you think about what is going on, this makes sense. For example, if we have a parabola and a line, intersection of the two curves may occur at two points. It is difficult to know just from the equations, how many points solve the system.
If you are allowed to, it helps to plot a graph on your calculator or computer and get a feel for what the graphs look like. This will help you know what to do when solving the equations.
Okay, now try your hand at some practice problems.
Practice
Unless otherwise instructed, find all the solutions to these nonlinear systems of equations, giving your answers in exact form.
Basic
\(y=x^2-9 \text{ and } y=9-x^2\)
Problem Statement |
|---|
\(y=x^2-9 \text{ and } y=9-x^2\)
Solution |
|---|
1777 video
video by MIP4U |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\(x^2-5y=6 \text{ and } x^2+y=18\)
Problem Statement |
|---|
\(x^2-5y=6 \text{ and } x^2+y=18\)
Solution |
|---|
1778 video
video by MIP4U |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\(2x^2-y^2=23 \text{ and } x^2+2y^2=34\)
Problem Statement |
|---|
\(2x^2-y^2=23 \text{ and } x^2+2y^2=34\)
Solution |
|---|
1779 video
video by MIP4U |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\(2x^2-10y^2=8 \text{ and } x^2-3y^2=6\)
Problem Statement |
|---|
\(2x^2-10y^2=8 \text{ and } x^2-3y^2=6\)
Solution |
|---|
1780 video
video by Brightstorm |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\(x^2+4x-y=7 \text{ and } 2x-y=-1\)
Problem Statement |
|---|
\(x^2+4x-y=7 \text{ and } 2x-y=-1\)
Solution |
|---|
1781 video
video by mattemath |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\(-x+y=4 \text{ and } x^2+y=3\)
Problem Statement |
|---|
\(-x+y=4 \text{ and } x^2+y=3\)
Solution |
|---|
1782 video
video by mattemath |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\(-2x+y=5 \text{ and } x^2+3x-y=1\)
Problem Statement |
|---|
\(-2x+y=5 \text{ and } x^2+3x-y=1\)
Solution |
|---|
1783 video
video by mattemath |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( y=x^2 \text{ and } 3x+y=10 \)
Problem Statement |
|---|
\( y=x^2 \text{ and } 3x+y=10 \)
Solution |
|---|
1789 video
video by Your Math Gal |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( x^2+y^2=25 \text{ and } 3x+4y=0 \)
Problem Statement |
|---|
\( x^2+y^2=25 \text{ and } 3x+4y=0 \)
Solution |
|---|
1790 video
video by Your Math Gal |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( y-x=4 \text{ and } x^2+8x=y-16 \)
Problem Statement |
|---|
\( y-x=4 \text{ and } x^2+8x=y-16 \)
Solution |
|---|
1791 video
video by Your Math Gal |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( 6x-y=5 \text{ and } xy=1 \)
Problem Statement |
|---|
\( 6x-y=5 \text{ and } xy=1 \)
Solution |
|---|
1792 video
video by Your Math Gal |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( y=x/2 \text{ and } 2x^2-y^2=7 \)
Problem Statement |
|---|
\( y=x/2 \text{ and } 2x^2-y^2=7 \)
Solution |
|---|
1784 video
video by Khan Academy |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( y=x+1 \text{ and } x^2+y^2=25 \)
Problem Statement |
|---|
\( y=x+1 \text{ and } x^2+y^2=25 \)
Solution |
|---|
1785 video
video by Khan Academy |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( y=-x^2+6 \text{ and }y=-2x-2 \)
Problem Statement |
|---|
\( y=-x^2+6 \text{ and }y=-2x-2 \)
Solution |
|---|
1786 video
video by Khan Academy |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( y=2x^2+3x-6 \text{ and } y=-x^2 \)
Problem Statement |
|---|
\( y=2x^2+3x-6 \text{ and } y=-x^2 \)
Solution |
|---|
1787 video
video by Khan Academy |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
\( y=2(x-4)^2+3 \text{ and } y=-x^2+2x-2 \)
Problem Statement |
|---|
\( y=2(x-4)^2+3 \text{ and } y=-x^2+2x-2 \)
Solution |
|---|
1788 video
video by Khan Academy |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
Intermediate
\( x^3 + 9x^2y = 10 \) and \( y^3 + xy^2 = 2 \)
Problem Statement |
|---|
\( x^3 + 9x^2y = 10 \) and \( y^3 + xy^2 = 2 \)
Hint |
|---|
Expand out \( (x + 3y)^3 \).
Problem Statement |
|---|
\( x^3 + 9x^2y = 10 \) and \( y^3 + xy^2 = 2 \)
Hint |
|---|
Expand out \( (x + 3y)^3 \).
Solution |
|---|
3784 video
video by blackpenredpen |
|---|
|
close solution
|
Log in to rate this practice problem and to see it's current rating. |
|---|
Really UNDERSTAND Precalculus
Topics You Need To Understand For This Page
Trig Formulas
The Unit Circle
The Unit Circle [wikipedia]
Basic Trig Identities
|
Set 1 - basic identities | |||
|---|---|---|---|
\(\displaystyle{ \tan(t) = \frac{\sin(t)}{\cos(t)} }\) |
\(\displaystyle{ \cot(t) = \frac{\cos(t)}{\sin(t)} }\) |
\(\displaystyle{ \sec(t) = \frac{1}{\cos(t)} }\) |
\(\displaystyle{ \csc(t) = \frac{1}{\sin(t)} }\) |
|
Set 2 - squared identities | ||
|---|---|---|
\( \sin^2t + \cos^2t = 1\) |
\( 1 + \tan^2t = \sec^2t\) |
\( 1 + \cot^2t = \csc^2t\) |
|
Set 3 - double-angle formulas | |
|---|---|
\( \sin(2t) = 2\sin(t)\cos(t)\) |
\(\displaystyle{ \cos(2t) = \cos^2(t) - \sin^2(t) }\) |
|
Set 4 - half-angle formulas | |
|---|---|
\(\displaystyle{ \sin^2(t) = \frac{1-\cos(2t)}{2} }\) |
\(\displaystyle{ \cos^2(t) = \frac{1+\cos(2t)}{2} }\) |
Trig Derivatives
\(\displaystyle{ \frac{d[\sin(t)]}{dt} = \cos(t) }\) |
\(\displaystyle{ \frac{d[\cos(t)]}{dt} = -\sin(t) }\) | |
\(\displaystyle{ \frac{d[\tan(t)]}{dt} = \sec^2(t) }\) |
\(\displaystyle{ \frac{d[\cot(t)]}{dt} = -\csc^2(t) }\) | |
\(\displaystyle{ \frac{d[\sec(t)]}{dt} = \sec(t)\tan(t) }\) |
\(\displaystyle{ \frac{d[\csc(t)]}{dt} = -\csc(t)\cot(t) }\) |
Inverse Trig Derivatives
\(\displaystyle{ \frac{d[\arcsin(t)]}{dt} = \frac{1}{\sqrt{1-t^2}} }\) |
\(\displaystyle{ \frac{d[\arccos(t)]}{dt} = -\frac{1}{\sqrt{1-t^2}} }\) | |
\(\displaystyle{ \frac{d[\arctan(t)]}{dt} = \frac{1}{1+t^2} }\) |
\(\displaystyle{ \frac{d[\arccot(t)]}{dt} = -\frac{1}{1+t^2} }\) | |
\(\displaystyle{ \frac{d[\arcsec(t)]}{dt} = \frac{1}{\abs{t}\sqrt{t^2 -1}} }\) |
\(\displaystyle{ \frac{d[\arccsc(t)]}{dt} = -\frac{1}{\abs{t}\sqrt{t^2 -1}} }\) |
Trig Integrals
\(\int{\sin(x)~dx} = -\cos(x)+C\) |
\(\int{\cos(x)~dx} = \sin(x)+C\) | |
\(\int{\tan(x)~dx} = -\ln\abs{\cos(x)}+C\) |
\(\int{\cot(x)~dx} = \ln\abs{\sin(x)}+C\) | |
\(\int{\sec(x)~dx} = \) \( \ln\abs{\sec(x)+\tan(x)}+C\) |
\(\int{\csc(x)~dx} = \) \( -\ln\abs{\csc(x)+\cot(x)}+C\) |
To bookmark this page and practice problems, log in to your account or set up a free account.
Topics Listed Alphabetically
Single Variable Calculus |
|---|
Multi-Variable Calculus |
|---|
Differential Equations |
|---|
Precalculus |
|---|
Search Practice Problems
Do you have a practice problem number but do not know on which page it is found? If so, enter the number below and click 'page' to go to the page on which it is found or click 'practice' to be taken to the practice problem.
|
| |
free ideas to save on bags & supplies |
|---|
The 17Calculus and 17Precalculus iOS and Android apps are no longer available for download. If you are still using a previously downloaded app, your app will be available until the end of 2020, after which the information may no longer be available. However, do not despair. All the information (and more) is now available on 17calculus.com for free. |
Page Sections
|
|---|
Save Up To 50% Off SwissGear Backpacks Plus Free Shipping Over $49 at eBags.com! |
Practice Instructions
Unless otherwise instructed, find all the solutions to these nonlinear systems of equations, giving your answers in exact form.
