17calculus
Limits Derivatives Integrals Infinite Series Parametrics Polar Coordinates Conics
Limits
Epsilon-Delta Definition
Finite Limits
One-Sided Limits
Infinite Limits
Trig Limits
Pinching Theorem
Indeterminate Forms
L'Hopitals Rule
Limits That Do Not Exist
Continuity & Discontinuities
Derivatives
Power Rule
Product Rule
Quotient Rule
Chain Rule
Trig and Inverse Trig
Implicit Differentiation
Exponentials & Logarithms
Logarithmic Differentiation
Hyperbolic Functions
Higher Order Derivatives
Differentials
Slope, Tangent, Normal...
Linear Motion
Mean Value Theorem
Graphing
1st Deriv, Critical Points
2nd Deriv, Inflection Points
Related Rates Basics
Related Rates Areas
Related Rates Distances
Related Rates Volumes
Optimization
Integrals
Definite Integrals
Integration by Substitution
Integration By Parts
Partial Fractions
Improper Integrals
Basic Trig Integration
Sine/Cosine Integration
Secant/Tangent Integration
Trig Substitution
Linear Motion
Area Between Curves
Volume
Arc Length
Surface Area
Work
Exponential Growth/Decay
Laplace Transforms
Describing Plane Regions
Infinite Series
nth-Term Test
p-Series
Geometric Series
Alternating Series
Telescoping Series
Ratio Test
Limit Comparison Test
Direct Comparison Test
Integral Test
Root Test
Absolute Convergence
Conditional Convergence
Power Series
Taylor/Maclaurin Series
Radius of Convergence
Interval of Convergence
Remainder & Error Bounds
Fourier Series
Study Techniques
Choosing A Test
Sequences
Infinite Series Table
Practice Problems
Exam Preparation
Exam List
Parametrics
Parametric Curves
Parametric Surfaces
Slope & Tangent Lines
Area
Arc Length
Surface Area
Volume
Polar Coordinates
Converting
Slope & Tangent Lines
Area
Arc Length
Surface Area
Conics
Parabolas
Ellipses
Hyperbolas
Conics in Polar Form
Vectors Vector Functions Partial Derivatives/Integrals Vector Fields Laplace Transforms Tools
Vectors
Unit Vectors
Dot Product
Cross Product
Lines and Planes
Angle Between Vectors
Direction Cosines/Angles
Vector Projections
Work
Triple Scalar Product
Triple Vector Product
Vector Functions
Arc Length
Arc Length Parameter
Unit Tangent Vector
Principal Unit Normal Vector
Curvature
Practice Exam A1
Partial Derivatives
Gradients
Directional Derivatives
Lagrange Multipliers
Tangent Plane
Practice Exam A2
Partial Integrals
Double Integrals
Area and Volume
Triple Integrals
Describing Plane Regions
Practice Exam A3
Vector Fields
Curl
Divergence
Conservative Vector Fields
Potential Functions
Parametric Curves
Line Integrals
Green's Theorem
Parametric Surfaces
Surface Integrals
Stokes' Theorem
Divergence Theorem
Practice Exam A4
Laplace Transforms
Unit Step Function
Unit Impulse Function
Square Wave
Shifting Theorems
Solve Initial Value Problems
Describing Plane Regions
Parametric Curves
Linear Algebra Review
Word Problems
Mathematical Logic
Calculus Notation
Simplifying
Greek Alphabet
Prepare For Calculus
Practice Exams
17calculus on YouTube
More Math Help
Tools and Resources
Academic Integrity
Learning/Study Techniques
Math/Science Learning
Memorize To Learn
Music and Learning
Note-Taking
Motivation
Instructor or Coach?
Books
Math Books
How To Read Math Books

You CAN Ace Calculus

17calculus > limits > continuity

precalculus
differential equations

Continuity

Continuity is something best learned from graphs to get a feel for it. Then you can go to equations to cement the concept in your head.

There are 3 parts to continuity. At this moment we are talking about continuity at a point.
For a function f(x) to be continuous at a point x = c all three of these conditions must hold.

1. \( f(c) \) is defined.

 

2. \( \displaystyle{\lim_{x \rightarrow c}{f(x)}} \) exists.

 

3. \( \displaystyle{\lim_{x \rightarrow c}{f(x)} = f(c)}. \)

If any one of these conditions is broken, then the function is not continuous at \(x=c\).
Let's look at graphs where each of the above conditions does not hold.

Condition 1: \( f(c) \) is not defined.
This graph shows an example of where the function is not defined at \(x=c\). So this function is not continuous at \(x=c\).

This is an example of a removable discontinuity. We can just redefine the function by redefining one point at \(f(c)\) to make it continuous.

Condition 2: \( \displaystyle{\lim_{x \rightarrow c}{f(x)}} \) does not exist.
Notice that the limit from the left is different than the limit from the right ( at \(x=c\) ). This means the limit does not exist.

This is an example of a non-removable discontinuity at \(x=c\). There is not way to 'plug the hole' or redefine the function at only one point so that the result is continuous.

Condition 3: \( \displaystyle{\lim_{x \rightarrow c}{f(x)} \neq f(c)}. \)
This graph shows an example of where the first two cases hold but the third doesn't, i.e. \(f(c)\) is defined, the limit exists but the limit does not equal \(f(c)\).

This is also an example of a removable discontinuity. Notice you can just move the \(f(c)\) to fill the hole to make the function continuous.

helpful? 35


Notes
1. Although not explicitly stated above, continuity holds in both directions, i.e. if a function is continuous then all three conditions hold and if all three conditions hold, then the function is continuous. So we can say, \(f(x)\) is continuous at \(x=c\) if and only if all three conditions listed above hold.
2. For case 2 above, where the limit must exist, sometimes we need to look at one-sided limits, i.e. limits from each side of the value we are talking about. You will find discussion, videos and practice problems on the one-sided limits page for this case.

Example Functions - - There are some functions that are guaranteed to be continuous on their domains. This is important . . . these functions are not necessarily continuous everywhere but they are continuous on their domains. We can use this information to build continuity information about other functions.

function type

example

polynomials

\(x^3+3x^2+1\)

rational functions

\( (x+3)/(x^2-1) \)

root functions

\( \sqrt{x+7} \)

trig functions

\( \sin(x) \)

logarithm functions

\( \ln(x-1) \)

Okay, now that you have an intuitive idea of continuity, let's watch some videos to help you understand and use continuity. It is important to watch both of them to get a complete picture of continuity.

1. This video explains continuity from a more mathematical viewpoint.

PatrickJMT - Continuity

2. This is a great video to watch to get a much better understanding of continuity using the limit definition. This is one of the best videos we've seen on youtube that explains a complicated math topic in a way that is understandable.

PatrickJMT - Continuity - Limit Definition

Okay, now that you have a better understanding of continuity, take a look at discontinuities explained in the next panel. There is a great video in this section that will help you a lot.

Discontinuities, Removable vs. Nonremovable; Zeroes, Holes and Asymptotes

Discontinuities, Removable vs. Nonremovable; Zeroes, Holes and Asymptotes

This discussion is going to cover several, seemingly diverse, topics. However, they are related in that the resulting equations are similar.

Discontinuities --- Removable vs. Nonremovable

First let's discuss the 3 main types of discontinuities: jumps, holes and asymptotes. Here are three graphs demonstrating each type.

Vertical Asymptote - - This graph shows the equation \(\displaystyle{ f(x) = \frac{1}{x-1} }\). At \(x=1\) we have a vertical asymptote. This is a nonremovable discontinuity, i.e. we can't redefine that function at \(x=1\) with one value that will make the function continuous there.

Notice in the equation that at \(x=1\), we have a zero in the denominator and a number (not zero) in the numerator.

Hole - - This plot shows the graph of the equation \(\displaystyle{ g(x)=\frac{x^2-1}{x-1} }\). At \(x=1\) we have a hole. This is a removable discontinuity since if we add the single point \((1,2)\) to the function, the result is a continuous function at \(x=1\).

Notice in the equation of \(g(x)\) that at \(x=1\), we have zero in the numerator and the denominator.

Jump - - In this third plot, we are graphing \(\displaystyle{ h(x) = \left\{ \begin{array}{rcl} x+1 & & x \leq 1 \\ x^2 & & x > 1 \end{array} \right. }\)
At \(x=1\) we have a jump. This is a nonremovable discontinuity since we can't redefine the function a single point to make it continuous at \(x=1\). Note: This graph is a piecewise function. For a review, go to the precalculus piecewise function page.

Here is a great video explaining discontinuities in more detail with lots of examples. Her example of what she calls a crazy graph is especially good. As an instructor, I have often put questions like this on exams.

IntegralCALC - Discontinuities

Zeroes, Holes and Asymptotes

Now let's look at the equations for each of these. I have included this with the discussion of discontinuities since two of these are discontinuities and the third, zeroes, are related to the other two but are not discontinuities. For this discussion, we are going to look how the equations are similar.

First let's look at zeroes. Zeroes of a function are sometimes called poles (especially in electrical engineering). Basically, they are points where the graph of a function crosses the x-axis, i.e. where \(y=0\). They are not discontinuities but are important points in mathematics and engineering. If you have a function that is a fraction such as \(\displaystyle{ f(x)=\frac{n(x)}{d(x)} }\), zeroes occur at x-values where the numerator function is zero but the denominator function is NOT zero. For example, look at the second graph above. A zero occurs at \(x = -1\). You can also say that there is a zero at the point \((-1,0)\). By definition, the y-value is zero, so we usually do not write the point \((-1,0)\). We usually just say \(x=-1\) or at \(-1\).

Okay, let's look at holes. If we have the a function in fraction form that looks like \(\displaystyle{ f(x)=\frac{n(x)}{d(x)} }\), holes occur at x-values where the numerator AND denominator are both zero at the same x-value. A hole is a discontinuity. Looking at the second graph above, we have a hole at \(x=1\) because the numerator and denominator of g(x) are both zero at \(x=1\).

Finally, vertical asymptotes occur at x-values where the denominator is zero but the numerator is NOT zero. Asymptotes are discontinuities. The first graph above shows this case. Notice that at \(x=1\), the numerator of f(x) is 1, but the denominator is zero.

Let's sum this up. For a fractional function in the form \(\displaystyle{ f(x)=\frac{n(x)}{d(x)} }\):
- Zeroes occur at x-values where \(n(x) = 0\) and \(d(x) \neq 0\)
- Holes occur at x-values where \(n(x) = 0\) and \(d(x) = 0\)
- Vertical Asymptotes occur at x-values where \(n(x) \neq 0\) and \(d(x) = 0\)
Here is the same information in table form.

\(n(x) \neq 0\)

\(n(x) = 0\)

Discontinuities?

\(d(x) \neq 0\)

Zero

No

\(d(x) = 0\)

Vertical Asymptote

Hole

Yes

helpful? 10

Intermediate Value Theorem

Intermediate Value Theorem

The intermediate value theorem is used to establish that a function passes through a certain y-value and relies heavily on continuity.

Intermediate Value Theorem

For a continuous function, \(f(x)\) on an interval \([a,b]\), if \( t \) is between \(f(a)\) and \(f(b)\),
then there exists a value \(c \in [a,b]\) such that \(f(c) = t\).


Notice that the theorem just tells you that the value \(c\) exists but doesn't tell you what it is or how to find it.
To get the idea of this theorem clear in your head, here are some great videos for you to watch. They use graphs to help you understand what the theorem means.

Here is a video that shows, graphically, how the intermediate value theorem works. She uses color in her graph to make it easy to follow.

IntegralCALC - Intermediate Value Theorem

Here is a great video that clearly explains the intermediate value theorem more from a mathematical point of view than in the previous video.

PatrickJMT - Intermediate Value Theorem

Application of the Intermediate Value Theorem - - Here is a great video showing a non-standard application of the IVT. To work this problem, he uses the definition of the limit. Don't skip this video. It will help you understand limits, continuity and the IVT.

Dr Chris Tisdell - IVT

faq: If a function has a nonremovable discontinuity at x = c, does x = c have to be a vertical asymptote?

If a function has a nonremovable discontinuity at x = c, does x = c have to be a vertical asymptote?

No, here is an example of a nonremovable discontinuity at \(x=c\) that is not a vertical asymptote. Click here for more information about nonremovable discontinuities.

helpful? 4

faq: What is a root of a function?

A root of a function is just a fancy word for an x-intercept, i.e. it is where the graph crosses the x-axis. The term root is often used in electrical engineering. You can also call a root, a zero ( since \(y=0\) ).

synonyms

root

zero

x-intercept

Note that you can have multiple roots of a function since a graph can cross with the x-axis multiple times without failing the vertical line test. [ which is why we talk about A root and not THE root ]

We discuss more about roots and how to determine if a function has a root from the equation in the panel on discontinuity above.

Search 17Calculus

Loading

filters

continuity

intermediate value theorem

Practice Problems

Instructions - - Unless otherwise instructed, solve the following practice problems, giving your answers in exact, completely factored form.

Level A - Basic

Practice A01

Classify the discontinuities (hole, asymptote. . .) of \(\displaystyle{f(x)=\frac{x-2}{x^2-4}}\) and determine which are removable.

answer

solution

Practice A02

Show that \(x^3-3x+1=0\) has a root in the interval \((0,1)\).

solution

Practice A03

\(\displaystyle{ g(x) = \left\{ \begin{array}{lr} x-3 & x \leq -1 \\ x^2+1 & -1 < x \leq 2 \\ x^3+4 & x >2 \end{array} \right. }\)
At what points is \(g(x)\) NOT continuous?

solution

Practice A04

Show that \(f(x)=x^4+x-3\) has a root in the interval \((1,2)\).

solution

Practice A05

\(\displaystyle{ f(x) = \left\{ \begin{array}{lr} x^2+3x & x < 0 \\ \sqrt{x}+1 & x \geq 0 \end{array} \right. }\)
At what points is \(f(x)\) NOT continuous?

solution

Practice A06

\(\displaystyle{ f(x) = \left\{ \begin{array}{lr} 2x+1 & x \leq -1 \\ 3x & -1 < x < 1 \\ 2x-1 & x \geq 1 \end{array} \right. }\)
At what points is \(f(x)\) NOT continuous?

solution

Practice A07

Show that \(x^2=\sqrt{x+1}\) has a root in the interval \((1,2)\).

solution

Practice A08

Classify any discontinuities of the function \(\displaystyle{ f(x)=\frac{x-2}{x^2-4} }\), then redefine the function at any removable discontinuities to make it continuous.

solution


Level B - Intermediate

Practice B01

Show that \(e^x=2\cos(x)\) has at least one positive root.

solution

Practice B02

\(\displaystyle{ f(x) = \left\{ \begin{array}{lr} x^2+3 & x < 1 \\ ax+6 & x \geq 1 \end{array} \right. }\)
What value of a makes the piecewise function \(f(x)\) continuous on the entire real line?

solution

Practice B03

\(\displaystyle{ f(x) = \left\{ \begin{array}{lr} c^2 - x^2 & x < 0 \\ 2(x-c)^2 & x \geq 0 \end{array} \right. }\)
What value of c makes the piecewise function \(f(x)\) continuous on the entire real line?

solution

Practice B04

Find where \(\displaystyle{f(x)=\sqrt[3]{\frac{x+1}{x-1}}}\) is continuous.

solution

Practice B05

Prove that \(\cos(x)=x^3\) has at least one real root.

solution

menu top search practice problems
5
17
menu top search practice problems 17